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3-2.Motion in Plane
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Two projectiles, one fired from surface of earth with velocity $10 \,m/s$ and other fired from the surface of another planet with initial speed $5\, m/s$ trace identical trajectories. The value of acceleration due to the gravity on the planet is ......... $m/s^2$
A
$2.5 $
B
$3.6$
C
$4.9 $
D
$6.4 $
Solution
$\mathrm{H}_{1}=\mathrm{H}_{2}$
$\frac{(10)^{2} \sin ^{2} \theta}{2 \mathrm{g}_{1}}=\frac{(5)^{2} \sin ^{2} \theta}{2 \mathrm{g}_{2}}$
$\frac{g_{2}}{g_{1}}=\frac{1}{4} \Rightarrow g_{2}=\frac{g_{1}}{4}=\frac{10}{4}=2.5 \mathrm{m} / \mathrm{s}^{2}$
Standard 11
Physics
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